Index block with PCTFREE 50
select extent_id, file_id,block_id from dba_extents where segment_name='IND_BMP_50' order by extent_id
 EXTENT_ID    FILE_ID   BLOCK_ID
---------- ---------- ----------
         0       1074      53953
         1       1115      53841
         2       1196      53745
         3       1742     447857
         4       1744     446833
SQL > alter system dump datafile 1742 block 447857
row#0[6126] flag: ------, lock: 0, len=1906
col 0; len 1; (1):  80                                <-key value
col 1; len 6; (6):  2b 40 d2 29 00 08    <-Starting Rowid
col 2; len 6; (6):  2b 40 d2 c1 00 1f     <-Ending Rowid
col 3; len 1886; (1886):                           <-Bitmap for the key value
row#1[4221] flag: ------, lock: 0, len=1905
col 0; len 1; (1):  80
col 1; len 6; (6):  2b 40 d2 c1 00 30
col 2; len 6; (6):  2b 40 d3 48 00 67
col 3; len 1885; (1885):
There are two rows in the block. Totallying their column size :
1+6+6+1886+1+6+6+1885 = 3797kb
So, block is occupying approx 50% of the block (8192kb)
Index block with PCTFREE 10
SQL> select extent_id, file_id,block_id from dba_extents where segment_name='IND_BMP_10' order by extent_id;
 EXTENT_ID    FILE_ID   BLOCK_ID
---------- ---------- ----------
         0       1074      63057
         1       1115      62945
         2       1196      62849
         3       1742     457377
         4       1744     456177
         5       1786     429665
         6       1809     411889
alter system dump datafile 1742 block 457377
row#0[4495] flag: ------, lock: 0, len=3537
col 0; len 1; (1):  80                                <-key value
col 1; len 6; (6):  b3 c6 f6 2b 00 28      <-Starting rowid
col 2; len 6; (6):  b3 c6 f6 ce 00 37       <-Ending rowid
col 3; len 3517; (3517):                           <-Bitmap for the key value
row#1[957] flag: ------, lock: 0, len=3538
col 0; len 1; (1):  80
col 1; len 6; (6):  b3 c6 f6 ce 00 48
col 2; len 6; (6):  b3 c6 f7 74 00 37
col 3; len 3518; (3518):
There are two rows in the block. Totallying their column size:
1+6+6+3517+1+6+6+3518 = 7161 kb
So, block is occupying approx 90% of the block (8192kb)
Wednesday, September 5, 2007
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